A projectile is launched at an angle of 30 degr... - SS2 Physics Mechanics - Motion in a Plane Question
A projectile is launched at an angle of 30 degrees above the horizontal with an initial velocity of 40 m/s. What is the maximum height reached by the projectile?
Given:
Initial velocity (V) = 40 m/s
Launch angle (θ) = 30 degrees
Acceleration due to gravity (g) = 9.8 m/s2
Using the kinematic equation: Vf2 = Vi2 + 2 x a x Δy
Since the maximum height is reached when the vertical velocity becomes zero, we can set Vf = 0.
0 = (40 x sin(30))2 + 2 x (-9.8) x Δy
0 = 400 x (1/2)2 - 19.6 x Δy
0 = 100 - 19.6 x Δy
Solving for Δy:
Δy = 100 / 19.6
Δy ≈ 5.102 metres
Therefore, the maximum height reached by the projectile is approximately 5.102 metres.
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